In poetry, a rose is a rose is a rose. On GMAT problems with central angle “slices” in circles, a fraction is a fraction is a fraction.

This may seem like common sense. Cut a pizza into six slices. If you cut it evenly, each slice now has one-sixth the cheese, one sixth the crust, and an angle of one sixth the way around a circle—that is, 60 degrees. However, though this may seem obvious, it’s actually a very useful technique for resolving certain geometry problems.

Consider the following Data Sufficiency question:

*In a radius 6 circle, two points A and B are connected to the center, point O. What is angle AOB?*

*1) **The length of the minor arc defined by sector O is 1.5**π*

*2) **The area of the sector defined by angle AOB is 4.5π*

It looks all GMAT-like and formal, but if you actually think about it…, it’s just the pizza I described above. We’re taking a slice, and want to know what’s the angle of that slice. The “cheese” of the pizza is the area of a radius 6 circle, which is the radius squared times pi, or 36π. The “crust” is it’s circumference, which in this case would be the diameter times pi, 12π.

Statement 1) tells us that the length of the arc/crust is 1.5π, which is 1.5/12 = 1/8 of the circumference. And an eighth is an eighth is an eighth. Our slice, which goes one eighth of the way around the outside of the circle, and it goes an eighth of the way around the inside of our circle as well—its central angle is 1/8 * 360 = 45 degrees. Sufficient!

And statement 2) says that the area of our slice/sector is 4.5π, or 4.5/36 = 1/8 the total area of the whole pie. Once again, an eighth is an eighth is an eighth, so by the exact same reasoning we get 45 degrees. Sufficient!

This is a pretty basic rule, but it’s widely applicable to many circle problems. It can be especially useful with central triangles, which have central angles by definition. Take a look at today’s question of the day to test your skills, and when you get it right, treat yourself to a slice of pepperoni as a reward!

**Question:**

What is the area of the circle above with center O?

(1) The area of D AOC is 18.

(2) The length of arc ABC is 3π.

**Answer:**

*Step 1: Analyze the Question Stem*

This is a Value question. For any Circle question, we

only need one defining parameter of a circle (area,

circumference, diameter, or radius) in order to calculate

any of the other parameters. Also, all radii of the same

circle will have the same length. So AO = CO. That makes

the triangle an isosceles right triangle (or 45-45-90) for

which we know the ratio of the sides. Not only would the

circle’s circumference, diameter, or radius be sufficient,

but information that gave us any side length of triangle

AOC would also be sufficient, as it would give us the length

of the radius.

*Step 2: Evaluate the Statements*

Statement (1): We are given the area, and we already know

that the base and the height are equal. So if we call the

radius of the circle r, then the area of the triangle is equal to

1/2 (Base)(Height) = 1/2 (r)(r) = 1/2 r ^2 = 18

Remember that we are not asked to calculate the actual

value of r. Because we have set up an equation with

one variable, and we know in this case that r can only

be positive since it is part of a geometry figure, we have

enough information to determine the area of the circle (the

solution would have been r ^2 = 36, r = 6).

Therefore, Statement (1) is sufficient. We can eliminate

choices (B), (C), and (E).

Statement (2): Because O is the center of the circle and

angle AOC measures 90 degrees, we know that the length

of arc ABC is one-fourth of the circumference. Because this

statement allows us to solve for the circumference, it is

sufficient.

(D) is correct.

Eli Meyer has been a Kaplan teacher since 2003. He has spent the past four years focused almost exclusively on the GMAT, and also has prior experience helping students ranging from middle-schoolers taking the ISEE to professors retaking the GRE for their second PhD. During his Kaplan career, Elis has also written and revised Kaplan course materials and acted as a community liaison on several popular GMAT message boards, all the while helping his students succeed both in and out of the classroom.