The correct answer is B.See the question again >
In a particular Hardy-Weinberg population, there are only two eye colors: brown and blue. 36% of the population has blue eyes, the recessive trait. What percentage of the population is heterozygous for brown eyes?
Using the information given to us in the question stem, we can determine that the percentage of the population with blue eyes (genotype bb) is 36%. In the Hardy-Weinberg equation, the homozygous recessive population is represented by the term q2; therefore, q2 = 0.36 and q = 0.6. Since this is a Hardy-Weinberg population, we know that p + q = 1, so p =0.4. Finally, the heterozygous population is represented by the term 2pq, or 2(0.4)(0.6) = 0.48. Thus, 48% of the population is heterozygous with a brown-eyed phenotype, making (B) the correct answer.
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