The correct answer is B.

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Using the information given to us in the question stem, we can determine that the percentage of the population with blue eyes (genotype bb) is 36%. In the Hardy-Weinberg equation, the homozygous recessive population is represented by the term q2; therefore, q2 = 0.36 and q = 0.6. Since this is a Hardy-Weinberg population, we know that p + q = 1, so p =0.4. Finally, the heterozygous population is represented by the term 2pq, or 2(0.4)(0.6) = 0.48. Thus, 48% of the population is heterozygous with a brown-eyed phenotype, making (B) the correct answer.