The correct answer is D.See the question again >
A nuclide undergoes 2 alpha decays, 2 positron decays, and 2 gamma decays. What is the difference between the atomic number of the parent nuclide and the atomic number of the daughter nuclide?
Remember that the atomic number of an element tells us the number of protons in the nucleus. In alpha decay, an element loses two protons and two neutrons. In positron decay, a proton is converted into a neutron. Gamma decay, meanwhile, has no impact on the atomic number . Therefore, two alpha decays and two positron decays will yield a daughter nuclide with 6 fewer protons than the parent.
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